4c^3+12c^2-40c=0

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Solution for 4c^3+12c^2-40c=0 equation:


Simplifying
4c3 + 12c2 + -40c = 0

Reorder the terms:
-40c + 12c2 + 4c3 = 0

Solving
-40c + 12c2 + 4c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '4c'.
4c(-10 + 3c + c2) = 0

Factor a trinomial.
4c((-5 + -1c)(2 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 3

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {0, -5, 2}

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